
@Article{hmt.13.27,
AUTHOR = {Yongbin Zhang},
TITLE = {INFLUENCE OF THE FLUID-WALL INTERACTION ON THE  MULTISCALE FLOW THROUGH A MICRO SLIT PORE CONSIDERING  THE ADSORBED LAYER-FLUID INTERFACIAL SLIPPAGE},
JOURNAL = {Frontiers in Heat and Mass Transfer},
VOLUME = {13},
YEAR = {2019},
NUMBER = {1},
PAGES = {1--6},
URL = {http://www.techscience.com/fhmt/v13n1/53161},
ISSN = {2151-8629},
ABSTRACT = {A multiscale analysis is carried out for the pressure driven flow rate through a micro/nano slit pore when the adsorbed layer-fluid interfacial slippage 
is considered. The flow of the adsorbed layer on the channel wall is described by the flow factor approach model for nanoscale flow, and the flow of 
the continuum fluid intermediate between the two adsorbed layers is described by a continuum fluid model. The adsorbed layer-fluid interfacial slippage 
is considered, while the adsorbed layer-wall surface interfacial slippage is ignored. The weak, medium-level and strong fluid-wall interactions and the 
solid adsorbed layer assumption are respectively taken. It is shown that when the thickness of the adsorbed layer is far lower than the continuum fluid 
film thickness, the adsorbed layer can be treated as a solid layer in spite of the fluid-wall interaction, otherwise the fluid-wall interaction has a significant 
influence on the critical power loss on the channel for motivating the interfacial slippage and on the total volume flow rate through the channel before 
the occurrence of the interfacial slippage; However, when the adsorbed layer-fluid interfacial slippage occurs, the fluid-wall interaction has a negligible 
influence on the normalized total volume flow rate through the channel vs. power loss on the channel curve and when using this curve for calculating 
the dimensionless volume flow rate through the channel the adsorbed layer can be taken as a solid layer. In general, only when the fluid-wall interaction 
is strong, the adsorbed layer can be taken as a solid layer in simulating the channel flow.},
DOI = {10.5098/hmt.13.27}
}



